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How to color elements within Graphics[Table[]] independently?
I've used a Table[] to generate multiple rounded squares, with Rectangle[{m, n}, RoundingRadius > .35]. So far, I've been able to color all the squares with the same color, for instance, with LightBlue:
Graphics[{EdgeForm[Black],
Table[{LightBlue, Rectangle[{m, n}, RoundingRadius > .35]}, {m,
5}, {n, 5}]}, Frame > True]
Or generate random colors for each square, for instance, with Hue[RandomReal[]]:
Graphics[{EdgeForm[Black],
Table[{Hue[RandomReal[]],
Rectangle[{m, n}, RoundingRadius > .35]}, {m, 5}, {n, 5}]},
Frame > True]
But, generally, I'd like to control the color of each of the squares independently, because I already have a vector of Hue[#] colors that I want to use. For instance, I'd like to use this 25 colors in correspondence to each of the (m,n) squares in the grid:
m=5;
n=5;
Split@Hue[#] & /@ Range[1/(m*n), 1, 1/(m*n)]
I've tried to do something like the following, but it doesn't seem right:
Graphics[{EdgeForm[Black],
Tab

Starting with slightly modified color code:
m = 5;
n = 5;
colors = Hue /@ Range[1/(m*n), 1, 1/(m*n)];
rectangles = Table[Rectangle[{m, n}, RoundingRadius > .35], {m, 5}, {n, 5}];
We may use either of these, among others of course:
Graphics[{EdgeForm[Black], {colors, Flatten@rectangles}\[Transpose]}, Frame > True]
Graphics[{EdgeForm[Black], Riffle[colors, Flatten@rectangles]}, Frame > True]
Reference Transpose and Riffle.
Also possible:
i = 1;
Graphics[{EdgeForm[Black],
Table[{colors[[i++]], Rectangle[{m, n}, RoundingRadius > .35]}, {m, 5}, {n, 5}]},
Frame > True]
20180218 21:06:17