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# Self-intro to mo-Roman numerals

2017-04-21 11:54:23

Here come mo -Roman numerals — just like

Roman

numerals,

only mo’ so.

(Explained as we go.)

What number can spell itself in two different ways

with mo-Roman letter substitution?

For example, the number 6

can spell itself in one way with mo-Roman letter substitution:

6

=

VX I

=

s i x

by substituting

V → s,

X → i   and

I → x

But, 6 =

VX I ?

Not the usual

V I ?

Both work in this system — the mo-Roman

the merrier!

Any smaller mo-Roman digit counts as negative

if it is written to the left of any larger digit.

Thus, when a smaller V is to the left of a larger X:

VX I

=

(−V)+X+I

=

(−5)+10+1

=

6

Self-spelling via mo-Roman substitution

also works for the number 19.

19

=

L I L XCXXL

=

n i n e t e e n

by substituting

L → n,

I → i,

X → e   and

C → t

Note that a smaller digit is negated even

when it does not touch the large

• This is kinda cheating, in fact very very cheating:

If you allow surjective-only mapping with alternative names, then you can make any number have multiple mo-Roman representation. (In my defense, I have humn's comment in the question)

The trick is the mapping:

$O,n,e\rightarrow I$; $a \rightarrow V$;(or any permutation, say $e,n,a \rightarrow I$ and $o \rightarrow V$, of this mapping) $d \rightarrow X$, so $oneand$ becomes $IIIVIX = (-1)+(-1)+(-1)+(-5)+(-1)+10 = 1$, so you can make $oneandoneand...$ to make the number you want.

For example,

$3$ becomes $oneandoneandoneand$ (sounds kinda stupid with the end "and") $= (-1)+(-1)+(-1)+(-5)+(-1)+10 + = (-1)+(-1)+(-1)+(-5)+(-1)+10 + = (-1)+(-1)+(-1)+(-5)+(-1)+10 = 1+1+1 =3$

2017-04-21 12:07:45