Self-intro to mo-Roman numerals

2017-04-21 11:54:23

Here come mo -Roman numerals — just like

Roman

numerals,

only mo’ so.

(Explained as we go.)

What number can spell itself in two different ways

with mo-Roman letter substitution?

For example, the number 6

can spell itself in one way with mo-Roman letter substitution:

6

  =  

VX I

  =  

s i x  

by substituting  

V → s,  

X → i   and  

I → x

But, 6 =

VX I ?

Not the usual

V I ?

Both work in this system — the mo-Roman

the merrier!

Any smaller mo-Roman digit counts as negative

if it is written to the left of any larger digit.

Thus, when a smaller V is to the left of a larger X:

VX I

  =  

(−V)+X+I

  =  

(−5)+10+1

  =  

6

Self-spelling via mo-Roman substitution

also works for the number 19.

19

  =  

L I L XCXXL

  =  

n i n e t e e n  

by substituting  

L → n,  

I → i,  

X → e   and  

C → t

Note that a smaller digit is negated even

when it does not touch the large

  • This is kinda cheating, in fact very very cheating:

    If you allow surjective-only mapping with alternative names, then you can make any number have multiple mo-Roman representation. (In my defense, I have humn's comment in the question)

    The trick is the mapping:

    $O,n,e\rightarrow I$; $a \rightarrow V$;(or any permutation, say $e,n,a \rightarrow I$ and $o \rightarrow V$, of this mapping) $d \rightarrow X$, so $oneand$ becomes $IIIVIX = (-1)+(-1)+(-1)+(-5)+(-1)+10 = 1$, so you can make $oneandoneand...$ to make the number you want.

    For example,

    $3$ becomes $oneandoneandoneand$ (sounds kinda stupid with the end "and") $ = (-1)+(-1)+(-1)+(-5)+(-1)+10 + = (-1)+(-1)+(-1)+(-5)+(-1)+10 + = (-1)+(-1)+(-1)+(-5)+(-1)+10 = 1+1+1 =3$

    2017-04-21 12:07:45