 Let $G$ be a group of order $p^2$ then $G$ is isomorphic to $\mathbb{Z}_{p^2}$ or $ \mathbb{Z}_p \times \mathbb{Z}_p$.
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 Trapezoidal rule
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 Find $f_x$ in terms of $f$
 Q. $\subset (9,4)$ is:
 distribution divergence metric that takes rank order into consideration
 Calculation related to second partial derivative
 The primitivity of ideals of a primitive ring
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 $k[X]/(F(X))\otimes_kk[Y]/(G(Y))\approx k[X,Y]/\langle f(X),g(Y) \rangle$
 Deriving 68% confidence level for each parameter after MCMC
 Proving tensor product over modules is commutative and associative
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 Still pretty confused with Argument Principle, Rouche's Theorem and Winding number
 Prove $2^e$ is transcendental
Selfintro to moRoman numerals
Here come mo Roman numerals — just like
Roman
numerals,
only mo’ so.
(Explained as we go.)
What number can spell itself in two different ways
with moRoman letter substitution?
For example, the number 6
can spell itself in one way with moRoman letter substitution:
6
=
VX I
=
s i x
by substituting
V → s,
X → i and
I → x
But, 6 =
VX I ?
Not the usual
V I ?
Both work in this system — the moRoman
the merrier!
Any smaller moRoman digit counts as negative
if it is written to the left of any larger digit.
Thus, when a smaller V is to the left of a larger X:
VX I
=
(−V)+X+I
=
(−5)+10+1
=
6
Selfspelling via moRoman substitution
also works for the number 19.
19
=
L I L XCXXL
=
n i n e t e e n
by substituting
L → n,
I → i,
X → e and
C → t
Note that a smaller digit is negated even
when it does not touch the large

This is kinda cheating, in fact very very cheating:
If you allow surjectiveonly mapping with alternative names, then you can make any number have multiple moRoman representation. (In my defense, I have humn's comment in the question)
The trick is the mapping:
$O,n,e\rightarrow I$; $a \rightarrow V$;(or any permutation, say $e,n,a \rightarrow I$ and $o \rightarrow V$, of this mapping) $d \rightarrow X$, so $oneand$ becomes $IIIVIX = (1)+(1)+(1)+(5)+(1)+10 = 1$, so you can make $oneandoneand...$ to make the number you want.
For example,
$3$ becomes $oneandoneandoneand$ (sounds kinda stupid with the end "and") $ = (1)+(1)+(1)+(5)+(1)+10 + = (1)+(1)+(1)+(5)+(1)+10 + = (1)+(1)+(1)+(5)+(1)+10 = 1+1+1 =3$
20170421 12:07:45